If you save the input as num,
this will print the input 8 times.
num = input("Enter a number: ")
print(num * 8)
If you want to do actual math calculations,
then the input needs to be a number.
num = float(input("Enter a number: "))
print(num * 8)
This doesn't account for any errors in which the user doesn't input a number, but I don't think that's what you were looking for anyway :)
Answer:
Image result for what is the name of the fields in an x.509 digital certificate that are used when the parties negotiate a secure connection?
Common applications of X. 509 certificates include SSL/TLS and HTTPS for authenticated and encrypted web browsing, signed and encrypted email via the S/MIME protocol, code signing, document signing, client authentication, and government-issued electronic ID.
Explanation:
Answer:
M1 is equal to $ 4 trillion
Explanation:
M1 money supplies are liquid money supplies like cash, checkable deposits, traveler's check etc. It is equal to;
M1= coins and currency in circulation + checkable (demand) deposit + traveler's check.
M2 money supply are less liquid and is equated as;
M2 = M1 + savings deposit + money market fund + certificates of deposit + other time deposits.
Savings = $7 trillion
Checkable deposit = $3 trillion
Money market fund = $1 trillion
Currency = $1 trillion
Certificates of deposit = $1 trillion
M1 = currency + checkable deposit
= $1 + $ 3
= $4 trillion.
Answer:
Explanation:
If it has not changed since the last time that i used codehs then the code should be the following
penup()
forward(-100)
right(90)
pendown()
def beaded_bracelet():
circle(10)
penup()
forward(20)
left(10)
pendown()
for i in range(36):
beaded_bracelet()
Which should complete the entire function as intended.
Answer:
The answer is output.open("yearsummary.txt", ios::trunc)
Explanation:
Given an ofstream object named output, associate it with a file named yearsummary.txt for output in a way that truncates (erases) any existing data in the file. The file is output.open("yearsummary.txt", ios::trunc)
