Answer:
a) t = 0,22 sec
b) 0.85 lts/sec
c) Interval for inhalation [ 0 < ( π/4.5 t) ≤ π ]
Interval for exhalation [ π < ( π/4.5 t ) ≤ 2π ]
Step-by-step explanation:
The respiratory cycle is approximated
r(t) = 0.85 sin (π/4,5t)
a) how long is the respiratory cicle.
As for problem statement a respiratory cicle is time between two consecutive breath
Then cycle will go from sin (π/4.5 t) = 0 to the position when sin (π/4.5 t) becomes negative that is when sin (π/4.5 t) < 0 or just after (π/4.5 t) is equal to π , so
sin (π/4.5 t) = sin (π) or (π/4.5 t) = π
solving for t t = π /π*4,5
t = 1/ 4,5
t = 0,22 sec
b) The maximum rate of air intake is when sin( π/4.5 t) takes its maximum value which is 1.
maxmum rate of air intake is: 0.85 lts/sec
c) Interval for inhalation [ 0 < ( π/4.5 t) ≤ π ]
Interval for exhalaton [ π < ( π/4.5 t ) ≤ 2π ]