Answer:
3π sq.feet
Step-by-step explanation:
Area of the square = L²
L is the length of the square
Given
Area of the square = 12 ft square
12 = L²
L = √12
L = 2√3 feet
Since the circle is inscribed in the square, the length of the square will be the diameter of the circle;
Area of the circle = πd²/4
Area of the circle = π(2√3)²/4
Area of the circle = 12π/4
Area of the circle = 3π sq.feet
Answer:
a) x = 1
Step-by-step explanation:
Given: 2x + 3 = 5
1. Subtract 3 from both sides:
2x + 3 - 3 = 5 - 3
⟹ 2x = 2
2. Divide both sides by 2:
2x ÷ 2 = 2 ÷ 2
⟹ x = 1
3. Check your work:
2(1) + 3 = 5
2 + 3 = 5
⟹ 5 = 5 ✔
Learn more about solving algebraic equations here:
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Every number has its purpose in this case you start at -3 then the negative sign tells you which way you are going but since we have another negative sign in between the number we go to the right instead of left with that said you put the point in number 4
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
