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Naddik [55]
4 years ago
9

What is the exact value of sin(-2pi/3)

Mathematics
2 answers:
Alex4 years ago
4 0

Answer:

opposite side       -√3

--------------------- = -------- = sin -2π/3

hypotenuse            2

Step-by-step explanation:

Note that +π/3 radians corresponds to +60°, and so +2π/3 radians corresponds to +120°.  Similarly,  -π/3 radians corresponds to -60°, and so -2π/3 radians corresponds to -120°.  

-2π/3 radians is in Quadrant III.  The "opposide" (the side opposite the angle) has length √3 when the radius of the circle is 2; because this angle is in Q III, we give it the - sign:  -√3.

Thus, the sine of -2π/3 is:

opposite side       -√3

--------------------- = -------- = sin -2π/3

hypotenuse            2

NemiM [27]4 years ago
3 0

Answer:

Unite circle

Step-by-step explanation:

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Which shows the graph of the solution set of 2x+3y≤6?
mel-nik [20]

Answer:

Option (a) is correct.

Step-by-step explanation:

 Given : equation  2x + 3y ≤ 6

We have to choose out of given option the graph that shows the graph of the solution set of 2x + 3y ≤ 6

Consider the given equation   2x + 3y ≤ 6

We first find the points where the equation cut x- axis and y-axis.

Thus,

For x - axis  put y = 0 ,

We get   2x + 3(0) ≤ 6 ⇒  2x  ≤ 6 ⇒ x ≤ 3

Thus, point (3,0)

For y - axis  put x = 0 ,

We get   2(0) + 3y ≤ 6 ⇒  3y  ≤ 6 ⇒ y ≤ 2

Thus, point (0,2)

For region we  choose a test point and find the value of x and y on that test point and  check whether it satisfy the inequality satisfies or not.

Consider the point (0, 0) , then inequality becomes,

2(0) + 3(0) ≤ 6  ⇒  0  ≤ 6 (true)

Hence, region below the line will be considered.

Thus, Option (a) is correct.

6 0
3 years ago
Read 2 more answers
Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
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