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4 years ago

Flight Distances

Mathematics

1 answer:

larisa86 [58]4 years ago

3 0

Answer:

4. Given that the distance from one place to another are placed in ranges of a thousand, then the distances from Sao Paulo to Chicago Illinois which is 5,252 miles and from Chicago Illinois to Istanbul Turkey which is 5,784 miles will be in the same 5,000 kilometer distance range and both distances will taken as the same distance

The same situation can also be arrived at by rounding down both distances

Step-by-step explanation:

The given information are;

The flight distances given;

From Sao Paulo to Chicago Illinois = 5,252 miles

From Chicago Illinois to Istanbul Turkey = 5,784 miles

From Beijing China to Chicago Illinois = 6,579 miles

Lees conjectured the flight distance from Chicago to Istanbul is the same as the flight distance from Chicago Sao Paulo when the distances are rounded to the nearest thousand

Placing the distances in ranges of 1000, we have the 5,252 miles and the 5,784 miles will be in the same 5,000 to 5,999 miles range.

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Consider h(x)=x^2+8+15. identify its vertex and y-intercept.

OleMash [197]

Answer:

Vertex: (-4, -1)

Y-intercept: (0, 15)

Step-by-step explanation:

Given the quaratic function, h(x) = x² + 8x + 15:

In order to determine the vertex of the given function, we can use the formula, $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ .

<h3>Use the equation: $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ </h3>

In the quadratic function, h(x) = x² + 8x + 15, where:

a = 1, b = 8, and c = 15:

Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.

$x = \frac{-b}{2a}$

$x = \frac{-8}{2(1)}$

x = -4

Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:

h(x) = x² + 8x + 15

h(-4) = (-4)² + 8(-4) + 15

h(-4) = 16 - 32 + 15

h(-4) = -1

Therefore, the vertex of the given function is (-4, -1).

<h3>Solve for the Y-intercept:</h3>

The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:

h(x) = x² + 8x + 15

h(0) = (0)² + 8(0) + 15

h(0) = 0 + 0 + 15

h(0) = 15

Therefore, the y-intercept of the quadratic function is (0, 15).

5 0

3 years ago

If kite ABCD is reflected across the x axis what are the results coordinates of point a

GenaCL600 [577]

Answer:

(-x,y)

Step-by-step explanation:

The x coordinate changes while the y stays the same when reflected across the x axis.

4 0

3 years ago

I don't know what -9/32 is

Levart [38]

Answer:

-0.28125

Step-by-step explanation:

8 0

4 years ago

I’m trying to help my brother with his homework but we both can’t solve this one

Ratling [72]

Well there are 2 pecks in 1 kenning
So that's 2 × 1 peck = 1 kenning

2 kennings in 1 bushel
That's 2 × 1 kenning = 1 bushel

2 bushels in 1 strike
That's 2 × 1 bushel = 1 strike

4 strikes in 1 quarter
That's 4 × 1 strike = 1 quarter

4 quarters in 1 chaldron
That's 4 × 1 quarter = 1 chaldron

So now substitute again and again:

4 × 1 quarter = 1 chaldron

4 × ( 4 × 1 strikers ) = 1 chaldron

4 × ( 4 × ( 2 × 1 bushel ) ) = 1 chaldron

4 × ( 4 × ( 2 × ( 2 × 1 kenning ) ) ) = 1 chaldron

4 × ( 4 × ( 2 × ( 2 × ( 2 × 1 peck ) ) ) ) = 1 chaldron

4×4×2×2×2 peck = 1 chaldron

128 peck = 1 chaldron

So that's 128 × 1 peck = 1 chaldron.

Hope this helps.

6 0

3 years ago

Estimate the error if t6 (trapeziod rule with n=6) was used to calculate ∫30cos(2x)dx.

Hunter-Best [27]

The error bound for a trapezoid rule is given with this formula:
$|E_t|\leq\frac{K(b-a)^3}{12n^2}$
Where n is the number of points we used in the approximation, a and b are starting and ending point of an integral, and K is the number such that:
$|f''(x)|\leq K$
In order to find K we must find the second derivative of our function:
$f(x)=30\cos(2x)\\ f'(x)=-60\sin(2x)\\ f''(x)=-120\cos(2x)$
From this, we can see that our K is 120. This is the amplitude of this periodic function.
Now we can calculate the error bound:
$E_t|\leq\frac{120(b-a)^3}{12\cdot6^2}=\frac{120}{432}(a-b)^3$
Since you did not specify the interval of integration I cannot compute the final error bound. You can simply plug in the numbers to get the answer.

7 0

3 years ago