Answer:
The trigger code is given below
create trigger F1_Del
after delete on Friend
for each row
when exists (select * from Friend
where ID1 = Old.ID2 and ID2 = Old.ID1)
begin
delete from Friend
where (ID1 = Old.ID2 and ID2 = Old.ID1);
end
create trigger F1_Insert
after insert on Friend
for each row
when not exists (select * from Friend
where ID1 = New.ID2 and ID2 = New.ID1)
begin
insert into Friend values (New.ID2, New.ID1);
end
Answer:
I did this in C# & Java
Explanation:
C#:
public static void Main(string[] args)
{
int input = Convert.ToInt32(Console.ReadLine());
Multiply(input);
}
public static int Multiply(int input)
{
int ans = 0;
for(int i =1; i<=10; i++)
{
ans = i*input;
Console.WriteLine(i + "*" + input + "=" + ans);
}
return ans;
}
Java:
public static void main(String[] args)
{
Scanner myObj = new Scanner(System.in);
int input = Integer.parseInt(myObj.nextLine());
Multiply(input);
}
public static int Multiply(int input)
{
int ans = 0;
for(int i =1; i<=10; i++)
{
ans = i*input;
System.out.println(i + "*" + input + "=" + ans);
}
return ans;
}
Steady sounds like the best answer but that’s tough
<h2><u>Given</u> :-</h2>
Create a HTML code for writing a web page for your school time-table.
<h2><u>Answer</u> :-</h2>
<html>
<head>
<title> Time Table </title>
</head>
<hrcolor = "red">
<hrcolor = "blue">
<body>
<table><tr = "7"><md = "7"><Period 1_></table>
</body>
</html>
Answered by - ItzMaster
The answer to this is verify the resources identified by experts
