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3 years ago

A solution with a ph 4 will contain more- ions and be more - than a solution with ph -

1 answer:

4 0

The pH scale is a logarithmic one, meaning that each pH unit has 10 times as many hydrogen ions as the unit above it. So, at pH 4, there are 10 times more hydrogen ions than at pH 5 and 100 times more hydrogen ions than at pH 6.

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Describe what role the components of the cell membrane play in defending the cell from viruses

Varvara68 [4.7K]

Answer:

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3 years ago

Second-growth forests ________.a) are those forests in the National Parks that are protected from logging b) are forests that es

AnnyKZ [126]

Answer:

Second-growth forests are forests that establish themselves after virgin timber has been removed from an area

Answer b) is the ANSWER

Explanation:

It's also known as secondary forest.

It occurs after a long time in a forest or woodland area where the disturbance factors have been removed over a long period of time. thereby, causing the regrowth of trees

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3 years ago

Which of these instruments is listed with the wrong type of lens that it uses?

AleksAgata [21]

Answer and Explanation:

$Hello,~Let's~answer~your~question!$

Q.Which of these instruments is listed with the wrong type of lens that it uses?

→ A.telescope, convex 

→ B.camera, convex 

→ C.flashlight, concave 

→ D.microscope, concave

→  $The~answer~for~this~question~is~option~D$ 

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Hope this helped you!

5 0

3 years ago

Brown fur is dominant to white fur in mice. in a population of mice, 64% have brown fur and 36% have white fur. based on these f

tester [92]

a. The frequency of the dominant allele: ___0.4______

b. The frequency of the recessive allele: ____0.6_____

c. The percentage of mice that are homozygous dominant: __16%_______

d. The percentage of mice that are heterozygous: _48%________

e. The percentage of mice that are homozygous recessive: __36%_______

Let us assign the dominant allele (that of brown hair) letter R while

We assign the recessive allele (that of white hair) letter r

We then note down the Hardy-Weinburg equation p2 + 2pq + q2 = 1

Brown fur population (p2 + 2pq) = 64% = 0.64

White fur population (q2) = 36% = 0.36

Then we also remember that the frequencies of both allele add up to 1 (p + q = 1);

Therefore q = ü.36 = 0.6

P = 1 – q = 1 – 0.6 = 0.4

The heterozygous population will be 2*0.6*0.4 = 0.48 = 48%

Homozygous domain population will therefore be (64% - 48%) = 16%

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3 years ago

What maternal physiological changes can be observed initially during the postpartum period?

Mila [183]

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3 years ago