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Savatey [412]
3 years ago
6

What is the answer i need help

Mathematics
1 answer:
Digiron [165]3 years ago
3 0
The answer is 6.875

1/2 = 0.5

0.5 * 0.5 * 0.5 = 0.125

7 - 0.125 = 6.875<span>
</span>
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Point G is between F and H. FH= 102, FG=5x+9, and HG=9x-5
dexar [7]

a)

FH = 102, FG = 5x + 9. HG = 9x - 5     <em>Given</em>

  FG    +   HG   =    FH                        <em>Segment addition postulate</em>

5x + 9 + 9x - 5 =  102                         <em>Substitution</em>

            14x + 4 = 102                        <em>Simplify (added like terms)</em>

                  14x = 98                          <em>Subtraction property of equality</em>

                     x = 7                             <em>Division property of equality</em>

b)   FG = 5x + 9  = 5(7) + 9   = 35 + 9   = 44

c)   HG = 9x - 5   = 9(7) - 5   = 63 - 5   = 58

Answers: a = 7, b = 44, c = 58

7 0
3 years ago
For the function f(x)=2^x the y intercept is (0,1). What is the y intercept of the function y=a•2^x?
Alex787 [66]

Answer:a

Step-by-step explanation:

7 0
3 years ago
Circle O has a center at (-2, 10) and a
allsm [11]

Answer:

B

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

distance =  \sqrt{(y1 - y2)^{2} +  {(x1 - x2)}^{2}  }

A. Distance between 2 points

=  \sqrt{ {(10 + 5)}^{2}  + ( - 2 + 6)^{2} }  \\  =  \sqrt{15 ^{2} +  {4}^{2}}  \\  =  \sqrt{241}  \\  = 15.524 \: units

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

=  \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2}  }  \\  =  \sqrt{ {6}^{2} }  \\  = 6 \: units

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

=  \sqrt{ {(10 - 4)}^{2}  +  {( - 2 - 6)}^{2} }  \\  =  \sqrt{ {6}^{2}  + ( - 8)^{2} }  \\  =  \sqrt{100}  \\  = 10 \: units

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

=  \sqrt{ {(10 - 8)}^{2}  +  {( - 2 - 8)}^{2} }  \\  =  \sqrt{2^{2}  + ( - 10)^{2} }  \\  =  \sqrt{104}  \\  = 10.198 \: units

(to 5 s.f.)

Point D also lies outside Circle O.

8 0
4 years ago
Mai runs around a track at a constant speed of 750 meters in 30 minutes . How many minutes per meter is that? And how many meter
Rudik [331]

Answer:

25 meters per minute

150 in 6 minutes

Step-by-step explanation:

5 0
3 years ago
Which function is symmetric with respect to the origin?
Kamila [148]

Answer:

uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

let me think

Step-by-step explanation:

8 0
3 years ago
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