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Savatey [412]
3 years ago
6

What is the answer i need help

Mathematics
1 answer:
Digiron [165]3 years ago
3 0
The answer is 6.875

1/2 = 0.5

0.5 * 0.5 * 0.5 = 0.125

7 - 0.125 = 6.875<span>
</span>
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Plz show work <br> 2(x+5)=26
Zolol [24]

Answer:

x = 8

Step-by-step explanation:

Step 1: Write equation

2(x + 5) = 26

Step 2: Solve for <em>x</em>

<u>Distribute 2:</u> 2x + 10 = 26

<u>Subtract 10 on both sides:</u> 2x = 16

<u>Divide both sides by 2:</u> x = 8

8 0
3 years ago
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I’ll mark Brainliest if correct ||question: which of the following shows the correct evaluation for the expression (2/5)^5
Nitella [24]

The 1st one

Well it's the same as normal exponents so you multiply  2/3 x 2/3 x 2/3 x 2/3 x 2/3

4 0
3 years ago
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This is a tricky one
IgorLugansk [536]
X = 12 , just solved it right now :)


3 0
3 years ago
A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip
DochEvi [55]

Answer:

The expression that represents the population of elk is: \text{elk}(t) = 2*3^t. It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at \text{elk}(0) = 2, then after the first year the population will be:

\text{elk}(1) = \text{elk}(0)*3 = 2*3

While on the second year, it'll be:

\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2

On the third year:

\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3

And so on, therefore the expression that describes the population of elk as the years passes is:

\text{elk}(t) = 2*3^t

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6

The population will reach 1,458 elk in 6 years.

8 0
3 years ago
The following sequence is arithmetic. 18, 11, 4, -3, -10, -17….
Romashka-Z-Leto [24]
Hello,

It is true that the sequence is arithmetic. Its common difference, of subtracting 7 each time, is always going to subtract 7 from each number.

Hope this helps!

May
3 0
3 years ago
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