Ask question

Ask question

All categories

3 years ago

15

There are three white marbles and seven blue marbles in a bag. Jamie will randomly pick two marbles out of the bag without repla

cing the first marble chosen. What is the probability of jamie picking two white marbles?

1 answer:

Goryan [66]3 years ago

8 0

The probability of Jamie picking a blue marble is greater. The ratio of this probability would be 7:3

You might be interested in

A cereal brand is on sale $2 for 32 oz. If Sally spent $8 on the cereal, how many ounces did she purchase?

Lelechka [254]

Answer:

it would be 128 because 8 divded 2 is 4. 4 is the number of cereal boxes now multiply 4 x32 which would be 128

3 0

3 years ago

Read 2 more answers

Which of the following graphs shows a parabola with a vertex of (1,-9) and solutions of (-2,0) and (4,0)?

Mariulka [41]

Answer:

Hello,

Step-by-step explanation:

Roots are -2 and 4

y=k*(x+2)(x-4)

Vertex = (1,-9) is a point of the parabola

-9=k*(1+2)(1-4) ==> k=1

Equation of the parabola is y=(x+2)(x-4)

But you don' t have given the graphs !!!!

3 0

2 years ago

Order these numbers from least to greatest.<br> 1.401, 1.2011, 1.2, 1.41

ira [324]

Answer:

From least to greatest, the correct order is 1.2, 1.2011, 1.401, and 1.41.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Whats 0.2 divide by 0.4 work and answer

alexdok [17]

Its is two since you take out the decimals then divide regularly

3 0

3 years ago

Read 2 more answers

If 3a-2b= 8 and a+3b=7 what is the value of 4a+b?

Fittoniya [83]

Step 1: Find the value of one variable in terms of the other.

$a+3b=7\\a=7-3b$

Step 2: Substitute the value you just found for this variable in the other equation.

$3a-2b=8\\3(7-3b)-2b=8\\21-9b-2b=8\\21-11b=8\\21=8+11b\\13=11b\\\frac{13}{11}=b\\ b=1\frac{2}{11}$

Step 3: Use your new value for the second variable to find the first.

$a+3b=7\\a+3(1\frac{2}{11})=7\\a+3\frac{6}{11}=7\\\\a=3\frac{5}{11}$

Now that we know the values for a and b we can find the value of 4a+b.

$4a+b\\4(3\frac{5}{11})+1\frac{2}{11}\\12+\frac{20}{11}+1\frac{2}{11}\\\\12+1\frac{9}{11}+1\frac{2}{11}\\\\\boxed{15}$

6 0

3 years ago