Question

I need help ASAP What is (g-f)(x)?

Answer 1

Step-by-step explanation:

g(x) = -x² - 1 - 2x

f(x) = x + 5

(g-f)(x) = g(x) - f(x)

(g-f)(x) = (-x² - 1 - 2x) - (x + 5)

(g-f)(x) = -x² - 2x - x - 1 - 5

(g-f)(x) = -x² - 3x - 6

Answer 2

Answer:

$-x^2-3x-6$

Step-by-step explanation:

$(g-f)(x)$ is simply the difference between the two functions $g(x)$ and $f(x)$. If $g(x)=-x^2-1-2x$ and $f(x)=x+5$, then

$(g-f)(x)=(-x^2-1-2x)-(x+5)\\(g-f)(x)=-x^2-1-2x-x-5\\(g-f)(x)=-x^2-3x-6$