2 years ago

16) The zero of a polynomial ax+b (a is not zero) isa/bb/a-a/b-b/a

Mathematics

1 answer:

Andreas93 [3]2 years ago

4 0

Answer:

x = - $\frac{b}{a}$ ( a ≠ 0 )

Step-by-step explanation:

To find the zero, let the polynomial equal zero, that is

ax + b = 0 ( subtract b from both sides )

ax = - b ( divide both sides by a )

x = - $\frac{b}{a}$

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The next three terms are: 1/6 , 0 and -1/6

Step-by-step explanation:

Given sequence is:

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First of all, we have to find the common difference

$here\\a_1 = \frac{5}{6}\\a_2 = \frac{2}{3}\\a_3 = \frac{1}{2}\\a_4 = \frac{1}{3}\\d = a_2-a_1 = \frac{2}{3} -\frac{5}{6} = \frac{4-5}{6} = -\frac{1}{6}\\d = a_3 - a_2 = \frac{1}{2} - \frac{2}{3} = \frac{3-4}{6} = =\frac{1}{6}$

The common difference is -1/6

We can simply add -1/6 to the previous term to find the next terms so,

Adding -1/6 to 1/3

$\frac{1}{3} - \frac{1}{6} = \frac{2-1}{6} = \frac{1}{6}\\\frac{1}{6} - \frac{1}{6} = 0\\0-\frac{1}{6} = -\frac{1}{6}$

Hence,

The next three terms are: 1/6 , 0 and -1/6

Keywords: Arithmetic sequence, common difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

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16) The zero of a polynomial ax+b (a is not zero) isa/bb/a-a/b-b/a​

16) The zero of a polynomial ax+b (a is not zero) isa/bb/a-a/b-b/a