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Iteru [2.4K]
3 years ago
9

N 0 Q. What are the solutions to the graphed system?

Mathematics
1 answer:
ira [324]3 years ago
7 0

Answer:

Answer is D

Step-by-step explanation:

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Please help asap, 20 points
s344n2d4d5 [400]

Solving for each equation:

A: True.

\frac{n}{2} +3 *4 = \frac{n}{2}+12\\\\\frac{n}{2} + 12 = \frac{n}{2} + 12

B: False.

\frac{1}{3}z+\frac{2}{3}z * 9 = 9z\\\\\frac{1}{3} z+6z = 9z

C: True, given that y = 1

-8y +4.3y + 3.7 = 0\\\\-3.7y = -3.7

D: True, given that b = 6.66667

12-1.8b+1.8b=1.8b\\12 = 1.8b

E: True.

\frac{m}{8} + 7(\frac{m}{8} ) =m\\\\\frac{m}{8} + (\frac{7m}{8} )= m\\\\\\\frac{8m}{8} = m\\

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3 years ago
In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether , they hit 18 home
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6 equals one person
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3 years ago
Which conversion factor below you can use to convert gallons to pints?
Korvikt [17]

Answer: 1 Cup = 8 fl oz

Step-by-step explanation:

7 0
3 years ago
!!!!!! Pls help !!!!!
Eduardwww [97]

Answer:

\underline{\boxed{m

Step-by-step explanation:

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6 0
3 years ago
Angles α and β are angles in standard position such that: α terminates in Quadrant II and sinα = 3/5, β terminates in Quadrant I
777dan777 [17]

We are given

Angles α and β are angles in standard position

and

α terminates in Quadrant II

β terminates in Quadrant I

and we have

sin(\alpha)=\frac{3}{5}

we can use triangle and find cos(α)

we get

cos(\alpha)=-\frac{4}{5}

and we have

cos(\beta)=\frac{4}{5}

we can draw triangle

sin(\beta)=\frac{3}{5}

now, we can use formula

cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)

now, we can plug values

cos(\alpha+\beta)=-\frac{4}{5}\times \frac{4}{5}-\frac{3}{5}\times \frac{3}{5}

now, we can simplify it

cos(\alpha+\beta)=-\frac{16}{25}-\frac{9}{25}

cos(\alpha+\beta)=-\frac{(16+9)}{25}

cos(\alpha+\beta)=-\frac{(16+9)}{25}

cos(\alpha+\beta)=-\frac{25}{25}

cos(\alpha+\beta)=-1...............Answer

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3 years ago
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