A leaky valve on the water meter overcharges the residents for one gallon of water every 1 1 over 3 months. The overcharged amou
nt w varies directly with time t. Find the equation that models this direct variation. How many months it will take for the residents to be overcharged for 5 gallons of water? A) w = 3 over 4t; 62 over 3 months.B) w = 4 over 3t; 62 over 3 months. C) w = 3 over 4t; 33 over 4 months. D) w = 4 over 3t; 33 over 4 months
The number of months overcharged for 1 gallon of leaky water = 1 1/3 = 4/3 Let us assume the quantity of water overcharged = w Let us assume the time in months = t Then, the equation modelling this direct variation is w = (3/4)t When w = 5, then 5 = (3/4) * t 20 = 3t t = 20/3 = 6 2/3 From the above deduction, we can conclude that the first option or option "A" is the correct option. I hope the answer helps you.
The correct answer to this question is letter "<span> A) w = 3 over 4t." </span>Given that the number of months overcharged for 1 gallon of leaky water is equal to 1 1/3 and which is equal to 4/3.
Let w the quantity of water overcharged Let t the time in months
Let's make the equation. We have to use direct variation. w = (3/4)t
w = 5, we will be able to get t 5 = (3/4) * t 20 = 3t t = 20/3 = 6 2/3
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