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olya-2409 [2.1K]
2 years ago
13

Ano ang rotasyon ng daigdig​

Computers and Technology
2 answers:
Alekssandra [29.7K]2 years ago
7 0
I’m confused. Is that a question?
Degger [83]2 years ago
6 0

Answer:  are you tying to ask a question

Explanation:

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why do networking components need more examination from an information security perspective than from a systems development pers
padilas [110]
Networking components will eventually interact with computers and devices outside of itself. Whereas during system development you are only interacting with your program internally.

For example, when you first work on a website you can begin working on it on your personal computer not connected to the outside world. When you are done working on your website you will now upload it to a webserver (or you will create your webserver) and now you are opening up the doors so to speak to the Internet. When you "open the door" you need to make sure the proper security is in place so that no one hacks your site. This is ussually done by making sure the webserver you are on does not have any known security vulnerbilities and has the proper firewall settings to prevent unauthorized access.
4 0
3 years ago
True or False: It is illegal to park in a location that you block or create a hazard for other vehicles.
Feliz [49]
The answer to question is true
5 0
3 years ago
Read 2 more answers
Which of the following does not make a good analysis class? (Points : 6) its name reflects its intent
satela [25.4K]

Answer:it has high coupling

Explanation: Coupling is the property in the field of computer program that is defined as the functions ,data and  codes of the program are dependent on each other and cannot be changed independently if requires. Thus,high amount of coupling is not considered as good factor due to high interdependence. Loose coupling can be still permitted.

Other options are correct because name of the class should reflect the purpose and well defined responsibilities should be present, modeling of certain component and high cohesion means keeping similar functions togather is also required. So, the only bad factor is high coupling

6 0
3 years ago
Which types of attacks are thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and spe
lesantik [10]

The types of attacks that are known to be thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and special characters are said to be Brute Force Attacks.

What is Brute Force Attacks?

This is known to be an attack that is said to be a very  crude type of attack and it is often seen as a brute-force attack.

Note that is one that does not depend on lists of passwords, but it is one that often tries all the  very possible combinations of permitted character types.

Hence, this type of attack was known to be historically seen as ineffective, and it is said to be The types of attacks that are known to be thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and special characters are said to be Brute Force Attacks.

Learn more about Brute Force Attacks from

brainly.com/question/17277433

#SPJ1

3 0
2 years ago
Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in t
neonofarm [45]

Answer:

1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

WHERE YEAR(o.OrderDate) = '1996'

GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

ORDER BY c.City, c.CustomerID

4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

HAVING COUNT(o.OrderID) > 3

ORDER BY c.City, c.CustomerID

5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p

JOIN Categories c

ON c.CategoryID = p.CategoryID

JOIN Suppliers s

ON s.SupplierID = p.SupplierID

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

where c.CategoryName = 'Grains/Cereals'

GROUP BY p.ProductID, p.ProductName, s.ContactName

ORDER BY SupplierName, p.ProductName

6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer

FROM Products p

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

JOIN Customers c

ON c.CustomerID = o.CustomerID

where YEAR(o.OrderDate) = 1996

GROUP BY p.ProductID, p.ProductName

Explanation:

The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.

8 0
3 years ago
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