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3 years ago

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Suppose you want to delete an existing file from within Word. What would you do? A. Click on the File button, choose Recent, ope

n the file, and select Delete. B. Click on Save As and give the file a new file name. C. Open the file in Word, click on Save As, and save the file to the Recycle Bin. D. Click on the File button, choose Save As, find the file, right click on the file, and select Delete.

Computers and Technology

1 answer:

koban [17]3 years ago

7 0

The asnwer would be A

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You have a website that sells widgets, and you have a category page specifically for blue widgets. After some extensive outreach

REY [17]

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It will increase your ranking on the homepage.

Explanation:

Widgets are easy to use software applications made up of one or more components.

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3 years ago

The type of database that is most capable of supporting complex data types is _____. Select one: a. sequential files b. relation

Anestetic [448]

Answer:

Object-Oriented DBMS.

Explanation:

Like classes in Object oriented programming Object-Oriented DBMS is can store objects.It follows an Object oriented data model with the properties of classes and the properties of Object oriented programming also.Objects can be in the form of complex data types or different data types.

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3 years ago

Read 2 more answers

Which of the following statements are TRUE about credit cards? I. When you use a credit card, the money comes directly out of yo

Svetllana [295]

i think it is 1. becuase it can be.

4 0

3 years ago

Express the following binary numbers in hexadecimal. (a) %100011100101 (b) %1011001111 (show work)

Lapatulllka [165]

Answer:

$(100011100101)_{2} = (8E5)_{16} = %8E5$

$(1011001111) = (2CF)_{16} = %2CF$

Explanation:

Binary and hexadecimal values have the following pair equivalences.

$(0000)_{2} = (0)_{16}$

$(0001)_{2} = (1)_{16}$

$(0010)_{2} = (2)_{16}$

$(0011)_{2} = (3)_{16}$

$(0100)_{2} = (4)_{16}$

$(0101)_{2} = (5)_{16}$

$(0110)_{2} = (6)_{16}$

$(0111)_{2} = (7)_{16}$

$(1000)_{2} = (8)_{16}$

$(1001)_{2} = (9)_{16}$

$(1010)_{2} = (A)_{16}$

$(1011)_{2} = (B)_{16}$

$(1100)_{2} = (C)_{16}$

$(1101)_{2} = (D)_{16}$

$(1110)_{2} = (E)_{16}$

$(1111)_{2} = (F)_{16}$

We convert from binary to hexadecimal selecting groups of 4 binary from the binary code, from the least significant bits(at the right) to the most significant bits(at the left). The conversion is an hexadecimal "string" from the last group you converted to the first. So:

(a) %100011100101

$(0101)_{2} = (5)_{16}$

$(1110)_{2} = (E)_{16}$

$(1000)_{2} = (8)_{16}$

So

$(100011100101)_{2} = (8E5)_{16}$

(b) %1011001111

$(1111)_{2} = F_{16}$

$(1100)_{2} = C_{16}$

$(10)_{2} = (0010)_{2} = 2_{16}$

$(1011001111) = (2CF)_{16}$

7 0

2 years ago

Help me help you...........

lyudmila [28]

Answer:

the 4th answer

Explanation:

w stage for width, h for height.

6 0

2 years ago