Answer:
7/9m=11/6 i believe is the answer.
Total Kenilworth students = 4 boys + 3 girls = 7.
Total students = 9+3+7+6+4+5=34.
So, the probability of a student from Kenilworth being called upon is 7/34=0.20588, or 20.588%
Answer:
1)
2)
3)
4)
5)
6)
7)
8)
9)
10)
Step-by-step explanation:
1)
Adding 7 to both sides
=> 2x > 3+7
=> 2x > 10
Dividing both sides by 2
=> x > 5
2)
Subtracting 11 to both sides
Multiplying both sides by 4
x ≥ -3 * 4
x ≥ -12
3) -6x+7 ≥ 19
Subtracting 19 to both sides
=> -6x ≥ 19-7
=> -6x ≥ 12
Dividing both sides by -6
=> x ≤ -2
4) -10 + 4x > 50
Adding 10 to b.s
=> 4x > 50+10
=> 4x > 60
Dividing b.s by 4
=> x > 15
5)
=> x < 4*-2
=> x < -8
6) 8 - 2x ≤ 46
Subtracting 8 from b.s
=> -2x ≤ 46-8
=> -2x ≤ 38
Dividing b.s by -2
=> x ≥ -19
7) -13x+1 ≤ -25
Subtracting 1 from both sides
=> -13x ≤ -25-1
=> -13x ≤ -26
Dividing both sides by -13
=> x ≥ 2
8)
Adding 7 to b.s
=> x/3 > -4+7
=> x/3 > 3
Multiplying 3 to b.s
=> x > 3*3
=> x > 9
9) -9x-19 ≥ 17
Adding 19 to both sides
=> -9x ≥ 17+19
=> -9x ≥ 36
Dividing both sides by -9
=> x ≤ -4
10) 16 - x > 9
Adding x to both sides
=> 16 > 9 + x
Subtracting 9 from both sides
=> 16 - 9 > x
=> 7 > x
OR
=> x < 7
NOTE: Whenever, we divide the inequality by a negative signed term, the inequality changes to its opposite.
The answer is the third option. add up all the test scores and divide them by the number of people whose scores you added
which would be three people