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shutvik [7]
3 years ago
15

Write a division problem whose quotient has its first digit in the hundreds place

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0
100*2=200 is one answer
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Need help please !!!
irina1246 [14]

sin^2 x + 4 sinx +3       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


factor the numerator


(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


cos^2 = 1-sin^2x

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

1- sin^2x                       1 - sinx

factor the denominator

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

(1-sinx ) (1+sinx)                   1 - sinx

cancel the common term (1+sinx)  and (sinx +1)

(sinx +3)                       3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx


reorder the first term

3+sinx                           3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx

3 0
3 years ago
Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o
Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box=12 m^3

height is 3 times the width

let height, length and breadth be H, L & B

H=3\times B

V=12=L\times B\times H

4=B^2\times L[/tex]

L=\frac{4}{B^2}

Cost of side walls $ 8/m^2

Cost of base $ 12/m^2

Cost of side walls=(2LH+2BH)\cdot 8

Cost of base =12LB

Total cost C=16LH+16BH+12LB

C=48LB+48B^2+12LB

C=\frac{192}{B}+48B^2+\frac{48}{B}

differentiate C w.r.t B to get minimum cost

\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}

B^3=\frac{240}{2\times 48}

B=1.35 m

H=3\times 1.35=4.07 m

L=2.19 m

C=$ 265.25

3 0
3 years ago
According to the text, what are two of Earth’s wind patterns? Choose two
pogonyaev

Answer:

Warm front and Cold Front I believe.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
At a certain college, 30% of the students major in engineering, 20% play club sports, and 10% both major in engineering and play
Mademuasel [1]

The probability that a student selected at random majors in engineering is 30% which is 0.3.

The probability  that the student both majors in engineering and play club sports is 10% which is 0.1.

For a student who is selected at random to be one who majors in engineering, there are two possible ways.

The student majors in engineering OR the Student both majors in engineering and plays club

The Probabilty that the student majors in Enginnering =

The probability that the student majors in engineering plus the  probability that Student both majors in engineering and plays club sport

= 0.3+0.1= 0.4

3 0
4 years ago
Find the values ofx and y.
Kitty [74]
Where do we find the answer from?
3 0
3 years ago
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