The lowest (or least) common denominator also written as LCD is the smallest of all the possible common denominators, where t<span>he </span>denominator<span> is the bottom number in a fraction.
</span>We should find the lowest common denominator of (p+3)/(p^2+7p+10) and <span>(p+5)/(p^2+5p+6).
</span><span>p^2+7p+10 can be written as a product: (p+5)(p+2)
</span>p^2+5p+6 <span>can be written as a product: (p+3)(p+2)
</span>So, we should find the LCD for (p+5)(p+2) and (p+3)(p+2). The smallest possible number that can be divided with both of them is:<span>(p + 5)(p + 2)(p + 3)
Solution C.</span>
Answer:
Any number by ten is the number and add how many 0's there are in an equation at the end. If you are doing it with decimals you would move one space to the right or left depending if it i negative or positive.
Step-by-step explanation:
If you times a number by ten and go the long way it will still equal up to the same number if you just add the amount of zero's it has in the equation to the end. Example's: 10x10=100 & 11x10=110.
Answer:
If there are 32 teams in the tournament and 1 winner, there were 31 games. So, 63 - 31 = 32 games.
X+3y=6
3y=-x+6
y=-(1/3)x+2
m=-1/3
y=mx+c
When y=2, x=-3, m=(-1/3),
2=(-1/3)*(-3)+c
2=1+c
c=1
So, the equation would be:
y=(-1/3)x+1
Hopefully that helps
