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LuckyWell [14K]
3 years ago
15

a school held a tennis tournament. after each round one fourth of the players were eliminated. if there were 64 players at the s

tart of the tournament, which equation models the number of players left after 6 rounds
Mathematics
2 answers:
Sveta_85 [38]3 years ago
8 0

Answer:

If there are 32 teams in the tournament and 1 winner, there were 31 games. So, 63 - 31 = 32 games.

 

ra1l [238]3 years ago
7 0

Step-by-step explanation:

you would do 64/1 • 1/4 to get 16 so every round 16 people would leave.

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Write words to match the expression for 36 divided by 4
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Answer - Thirty Six Divided By Four Is Equal To Nine.
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In a circle, the circumference and diameter vary directly. Which of the following equations would allow you to find the diameter
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The answer is <span>B.154/d = 44/14 
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<span>In a circle, the circumference (C) and diameter (D) vary directly:
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3 years ago
Solve for k.<br> 11<br> k<br> 11<br> 8<br> 4<br> k= ?
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Step-by-step explanation:

4 0
3 years ago
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Given: KLMN is a trapezoid, m∠N=m∠KML, FD=8, LM KN = 3 5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 5 Find: KM
denis23 [38]

Answer:

The length of side KM is \sqrt{109} units.

Step-by-step explanation:

Given information:  KLMN is a trapezoid, ∠N= ∠KML, FD=8, LM:KN=3:5, F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3\sqrt{5}.

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is 3\sqrt{5}.

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since LM:KN=3:5, therefore LM is 3x and KN is 5x.

\frac{3x+5x}{2}=8

\frac{8x}{2}=8

x=2

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

KN=KA+AE+EN

10=6+2(EN)                (KA=EN, isosceles trapezoid)

EN=2

KE=KN-EN=10-2=8

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

Hypotenuse^2=base^2+perpendicular^2

(KM)^2=(KE)^2+(ME)^2

(KM)^2=(8)^2+(3\sqrt{5})^2

KM^2=64+9(5)

KM=\sqrt{109}

Therefore the length of side KM is \sqrt{109} units.

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3 years ago
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