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Alla [95]
3 years ago
8

Need help on question 5 please help

Mathematics
1 answer:
blagie [28]3 years ago
4 0

Answer:

  $66

Step-by-step explanation:

It can be convenient to assign a different variable to the amount of money each spent. We can call the amounts spent by Seedevi, Georgia, and Amy "s", "g", and "a", respectively.

The problem statement tells us ...

  s = (1/2)g

  s = a +6

  s + g + a = 258

__

The problem statement asks for the amount Seedevi spent, so we need to find the value of s. It is convenient to write the other variables in terms of s:

  g = 2s

  a = s -6

Then the sum is ...

  s + (2s) +(s -6) = 258

  4s = 264 . . . . . . . . . . . add 6, simplify

  s = 66 . . . . . . . . . . . . . .divide by 4

Seedevi spent $66.

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3 years ago
Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How m
8_murik_8 [283]

Value of the given statement:

  1. 4.36
  2. 5
  3. 6
  4. 38
<h3>What is Probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

According to the given information:

1) There are a total of 10 slips after adding.

8 slip with 3 on it

2 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 11)  x 3 + (2/ 11)  x 9

24 / 11 + 24 / 11 = 4.36

2 )No of total slips after addition = 12

8 slip with 3 on it

4 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 12)  x 3 + (4 / 12)  x 9

2 + 3 = 5

3 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 6

24 + 18 + 9n / 10 + n  = 6

42 + 9n = 60 + 6n

3 n = 18

n = 6

4 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

expectation value = probability of 3 x 3 + probability of 9 x 9

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 8

24 + 18 + 9n / 10 + n  = 8

42 + 9n = 80 + 8n

n = 38

Minimum of 38 has to be added .

To know more about Probability visit:

brainly.com/question/17487084

#SPJ4

I understand that the question you are looking for is:

1:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add one additional $9$ to the bag? 2:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add two additional $9$'s (instead of just one) to the bag? 3:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do we have to add to make the expected value equal to $6$? 4:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do I have to add before the expected value is at least $8$?

4 0
2 years ago
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