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sergiy2304 [10]
3 years ago
15

Which of the following statements is not true concerning the equation x2−c=0 for c>0? A. The​ left-hand side of this equation

is called a difference of two squares. B. This equation is not considered to be a quadratic equation because it is not of the form ax2+bx+c=0. C. A quadratic equation in this form can always be solved by factoring. D. A quadratic equation in this form can always be solved using the square root property.
Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

The correct option is;

B. This equation is not considered to be a quadratic equation because it is not in the form a·x² + b·x + c = 0

Step-by-step explanation:

A. The given equation, x² - c = 0, can be presented in the form of the difference of two squares as follows;

(x + √c)·(x - √c) = 0

B. The equation x² - c = 0, is a quadratic equation because it is a polynomial equation of degree 2

C.  The equation x² - c = 0 can always be factored as (x + √c)·(x - √c) = 0

D. Where c > 0, the equation x² - c = 0 can by the square root property as follows;

x² - c = 0

x² = c

x = √c

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Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
3 years ago
A small garden measures 8 ft by 7 ft. A uniform border around the garden increases the total area to 110 ft 2. What is the width
Alik [6]

Answer: 3

Step-by-step explanation:

You can answer this question by using the equation

(8+x)(7+x)=110

The x represents the width, as we do not know the area. If you simplify the equation, it becomes 56+15x+x2=110.

If you move all the terms to the left side, and rearrange it, it can become x^2+15x-54=0

This can be simplified into (x-3)(x+18)=0

This equation makes it so that x is either 3 or -18. It is not possible for a width to be -18, so the width must be 3.

8 0
3 years ago
An angelfish was 1 1/2 inches long when it was bought. Now it is 2 1/3 inches long.
____ [38]

A)

Earlier, The length of the angelfish  = 1 \frac{1}{2} inches

Now, the length of angelfish = 2 \frac{1}{3} inches

We have to determine the grown length of angelfish

=  2 \frac{1}{3} -  1 \frac{1}{2}

= \frac{7}{3}- \frac{3}{2}

LCM of '2' and '3' is '6',

= \frac{14-9}{6}

= \frac{5}{6} inch

Therefore, the angelfish has grown by \frac{5}{6} inch.

B)

We have to determine the increased length of angelfish in feet.

Since 1 inch = \frac{1}{12} foot

So, \frac{5}{6} inch = \frac{5}{6} \times \frac{1}{12} = \frac{5}{72}

= 0.069 foot.

7 0
3 years ago
Read 2 more answers
Please help, Math is not for me
Bond [772]

Answer:

-25

Step-by-step explanation:

-5 * -5= -25

7 0
3 years ago
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Which of the following points is in the solution set of y &gt; -x2 + 5?
Stella [2.4K]
Its the third option (2, 4)
7 0
3 years ago
Read 2 more answers
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