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Leona [35]
3 years ago
11

In medical experiments, half of the participants are given the medication, and the remaining participants are given a placebo. A

placebo is an inactive substance such as a sugar pill that looks identical to the medication. By utilizing a placebo, the study remains free from being altered as neither the participants nor the researcher knows who is receiving the medication.
Comparison:
Random assignment:
Control:
Replication:


Is this a blind experiment or a double blind experiment? Why or why not?
Mathematics
1 answer:
Advocard [28]3 years ago
4 0

Answer:

huh I don't know that can u

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Find the total volume. Please show your work.​
elena-s [515]

Answer:

Step-by-step explanation:

You have a half sphere and a cylinder.

Trick question! Note that the diameter of the cylinder is in meters, while the height is given in centimeters.

For cylinder:

 radius r = 5 m

 height h = 6 cm = 0.06 m

 volume = πr²h = π(5²)(0.06) = 1.5π m³

For sphere:

 radius r = 5 m

 volume of sphere = (4/3)πr³

 volume of half sphere =  (2/3)πr³ = (2/3)π5³ = (250/3)π m³

Total volume = 1.5π + 250π/3 ≅ 266.5 m³

4 0
3 years ago
Find the surface area of a cone if the diameter of its base is 13.5 feet, and it has a slant height of 16.8 feet. Round to the n
Tresset [83]

The diameter is given which is 13.5feet and radius is half of diameter. Therefore radius = 6.75 feet.

Slant height = 16.8 feet

The formula of surface area of cone is

S = \pi *r(r+l) \\ S = \pi*6.75(6.75+16.8) \\ S =\pi*6.75*23.55 = 499.2 ft^2

Correct option is C

5 0
3 years ago
Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
What is the explicit formula for this arithmetic sequence? -11, -18, -25,-32,...
marusya05 [52]
D iaitu (beza sepunya)=T2(sebutan kedua)-T1(sebutan pertama)
4 0
3 years ago
(PLEASE HELP)
stich3 [128]

Answer:

C

Step-by-step explanation:

Because you should be subtract each other by 20x to transfer from side to another side.

4 0
3 years ago
Read 2 more answers
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