the bicycle wheel rotates 5 times and travels 37.94 feet, then we know that the circumference of the wheel (the outside of the wheel as it touches the ground 5 times around) is 37.94/5 = 7.588

Then we use the formula for the circumference of a circle: 2(pi)(radius) = circumference

We plug in what we know 2(3.14)(radius) = 7.588 and then solve for the radius

We divide 2 from both sides of the equation (3.14)(radius) = 3.794

We divide pi from both sides (radius) = 1.208

Then the last step, we multiply the radius by 2, because we need the diameter, which is double the radius

1.208 * 2 = 2.416 or 2.42 rounded up

Final answer = 2.42 feet

7 0

2 years ago

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Please help me with this!<br> I will give you a thanks!

Grace [21]

-2 + 6
.................

4 0

3 years ago

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Find cot θ if csc θ = negative square root of thirty seven divided by six and tan θ > 0.

Ket [755]

You can use the trigonometric identity $1+\cot^2{x}=\csc^2{x}$ .

$1+\cot^2{\theta}=(\frac{-\sqrt{37}}{6} )^2 \\ 1+\cot^2{\theta}=\frac{37}{36} \\ \cot^2{\theta}=\frac{1}{36} \\
\cot{\theta}=\frac{1}{6}$

The requirement that $\tan{\theta}\ \textgreater \ 0$ eliminates -1/6 from being another solution.

6 0

2 years ago