Answer:
a) The expected value of the mean of the 49 randomly selected students, M, is 7.06 digits
b)
The Standard error of the mean is 0.2328
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given sample size 'n' = 49
The Expected value of the mean of 49 randomly selected students
μₓ = μ =7.06 digits
b)
<em>The Standard error of the mean determined by</em>
<em></em>
<em></em>
Given sample size 'n' = 49
<em>The Standard deviation 'σ' = 1.63 digits</em>
<em>The Standard error </em>
![S.E = \frac{S.D}{\sqrt{n} }](https://tex.z-dn.net/?f=S.E%20%3D%20%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D)
![S.E = \frac{1.63}{\sqrt{49} } = 0.2328](https://tex.z-dn.net/?f=S.E%20%3D%20%5Cfrac%7B1.63%7D%7B%5Csqrt%7B49%7D%20%7D%20%3D%200.2328)
<u><em>Final answer</em></u>:-
a) The expected value of the mean of the 49 randomly selected students, M, is 7.06 digits
b)<em> The Standard error of the mean is 0.2328</em>