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olga55 [171]
3 years ago
8

Which product is equivalent to 25 x 2 - 16​

Mathematics
2 answers:
never [62]3 years ago
4 0

34 is equivalent to 25×2-16.

Gwar [14]3 years ago
3 0

Answer:

34

Step-by-step explanation:

25 x 2 = 50 -16 = 34 meaning that you get the product

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Show that 1/ 1+ √2 + 1 /√2+√3 = -1 + √3
m_a_m_a [10]

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4 years ago
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Using the following image, solve the problems below given that Q is the midpoint of PR.​
DochEvi [55]

Answer:

x=18

pq=101

qr=101

pr=202

Step-by-step explanation:

6x-7=5x+11

+5x pasa a restar como -5x al primer miembro y -7 pasa como +7x al segundo miembro y la ecuacion quedaria asi:

6x-5x=11+7

6x-5x=x

11+7=18

entonces x=18

pq=6x-7

pq=6(18)-7

pq=108-7

pq=101

y como se sabe que pq=qr porque hay un punto medio y dos segmentos cuando los divide un punto medio esos dos segmento miden igual entonces

por eso pq=qr

y como pq=101  qr=101

por ultimo

pr=pq+qr

pr=101+101

pr=202

3 0
4 years ago
For the functions u(t) = 8t – 14 and<br> s(t) = t2– 16, what is s (u (3))?
hjlf

Answer:

Step-by-step explanation:

u(3) = 8(3) - 14 = 24 - 14 = 10

s(10) = 10^2 - 16 = 100 - 16 = 84

6 0
3 years ago
How many positive integers less than 100 have at least one digit that is a 9? (Let T be the set of positive integers less than 1
Ymorist [56]

Answer:

19

Step-by-step explanation:

Let T be the set of positive integers less than 100 with a 9 in the ten's place.

T = {90, 91, 92, 93, 94, 95, 96, 97, 98, 99}

n(T) = 10

Let O be the set of positive integers less than 100 with a 9 in the one's place.

O = {9, 19, 29, 39, 49, 59, 69, 79, 89, 99}

n(O) = 10

The common element is 99.

T\cap O={99}

n(T\cap O)=1

The union of both sets is

n(T\cup O)=n(T)+n(O)+n(T\cap O)

n(T\cup O)=10+10-1

n(T\cup O)=19

Therefore, 19 positive integers are less than 100 those have at least one 9.

6 0
4 years ago
Help me plz plz guys
alexira [117]
What grade are you in? I'm sorry but I can't help you because I don't know how to do that :(
8 0
3 years ago
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