Show that 1/ 1+ √2 + 1 /√2+√3 = -1 + √3
2 answers:
Answer:
See below.
Step-by-step explanation:
1/( 1+√2) + 1 /(√2+√3)
Multiply both fractions by the conjugate of the denominators:
= (1 -√2) / (1 +√2)(1 - √2) + (√2 - √3) / (√2 + √3)(√2 - √3)
= (1 - √2) / -1 + (√2 - √3) / -1
= -1 + √2 - √2 + √3
= -1 + √3 as required.
Answer:
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