Three bags of sweets weigh 6 3/4 kg. Two of them have the same weight and the third bag is heavier than each of the bags of equa
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Given :
A T.V. is measure by its diagonal.
To Find :
If the height of a 60 inch T.V. is 32 inches, what is the width.
Solution :
We know, T.V. is rectangular in shape and angle between two sides of rectangular is 90° .
Let, width of T.V. is x.
Applying Pythagoras theorem in sides, we get :
Therefore, width of T.V. is 55.42 inches.
Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
