A) The dimensions are (x+10) by (x+10).
B) The perimeter is given by 4x+40.
C) The perimeter when x is 4 is 56.
The quadratic can be factored by finding factors of <em>c</em>, the constant, that sum to <em>b</em>, the coefficient of <em>x</em>. Our <em>c</em> is 100 and our <em>b</em> is 20; we want factors of 100 that sum to 20. 10*10=100 and 10+10=20, so those are what we need. This gives us (x+10)(x+10 for the factored form.
Since the dimensions are all (x+10), and there are 4 sides, the perimeter is given by 4(x+10). Using the distributive property we have 4*x+4*10=4x+40.
To find the perimeter when <em>x</em>=4, substitute 4 into our perimeter expression:
4*4+40=16+40=56.
Answer:
The median for Springwood is 86 and the median for Meadows is 73. The interquartile range for Springwood is 14. The interquartile range of Meadows is 12.
Step-by-step explanation:
The median is the middle line of a box plot. The interquartile range is the is third quartile minus the first quartile.
Answer:
The answer is b. But you asked for the thought process so...
Step-by-step explanation:
Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
We know that
Speed = Distance/Time.
Or, Time = Distance/Speed.
So, the time taken to cover a distance of 50 miles on his first trip = 50/x hr.
And the time taken to cover a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
So we can clearly see that his new time compared with the old time was: twice as much.
Have a great day :)
<u>For this question, I will be writing 'csc' instead of 'cosec'</u>
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