All categories

3 years ago

Given that (9,-8) is on the graph of f(x), find the corresponding point for the function f(x-2)

Mathematics

1 answer:

MrRa [10]3 years ago

4 0

Answer:

(11,-8)

Step-by-step explanation:

f(x-2) determines a horizontal translation 2 units to the right. Since (9,-8) is the point for f(x) then f(x-2) will be the point (11,-8) where 9 has moved two units to the right 11.

You might be interested in

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

(b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

Each letter of the word "supercalifragilisticexpialidocious" is placed into a bag and drawn at 3 times, replacing the letter aft

Makovka662 [10]

Answer:

P(X ≥ 1) = 0.50

Step-by-step explanation:

Given that:

The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.

Then; the probability of success = 7/34 = 0.20588

Using Binomial distribution to determine the probability; we have:

$P(X = x) = ^nC_x \ \beta^x \ (1 - \beta)^{n-x}$

where;

x = 0,1,2,...n and 0 < β < 1

and x represents the number of successes.

However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:

P(X ≥ 1) = 1 - P(X< 1)

P(X ≥ 1) = 1 - P(X =0)

$P(X \ge 1) = 1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]$

$P(X \ge 1) = 1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]$

P(X ≥ 1) = 1 - 0.50

P(X ≥ 1) = 0.50

4 0

3 years ago

Help me if u can and thank you :)

DanielleElmas [232]

Answer:

320km = 12L

296 km = xL

x = (296 × 12)/320

x = 11.1 liters

3 0

3 years ago

Read 2 more answers

Solve the system of equations using a matrix.<br> x + 5y = 14<br> 4x-y = 35

marshall27 [118]

Answer: x = 14 - 5y
y = 14/5 - x/5( if you solve for y )

2nd one x = 35/4 + y/4
y = -35 +4x ( solve for y )

4 0

3 years ago

An employee of a store's gift wrapping center is wrapping 8 gifts

Hitman42 [59]

The area A of a rectangle is A = bh, where b is the base of the rectangle and h is the height. The area of each rectangle with side lengths 1.5 ft and 2 ft is 1.5 × 2 = 3ft2. Since there are two rectangles with these dimensions, the combined area is 2 × 3 = 6 ft2. The area of each rectangle with side lengths 1.5 ft and 2.5 ft is 1.5 × 2.5 = 3.75 ft2. The area of each rectangle with side lengths 2 ft and 2.5 ft is 2 × 2.5 = 5 ft2. Since there are two rectangles of each type, the combined area is 2 × 3.75 + 2 × 5 =17.5 ft2. <u><em>So, the total surface area of the box is 6 ft2+ 17.5 ft2 = 23.5 ft2</em></u>

The employee needs to wrap 8 boxes, each with a surface area of 23.5 ft2. So, the combined surface area needing to be wrapped is 8 × 23.5 = 188 ft2. Since there is only 160 square feet of wrapping paper left, the employee will not be able to wrap all of the gifts

6 0

2 years ago