If AB is parallel to CD, then A’B’ is parallel to C’D’.
The distance between two positions with longitudes A and B is given by ||A| - |B|| if the two positions are at the same side of the meridian (0 degrees longitude) and |A| + |B| if both positions are at different sides of the meridian.
Given that <span>Moscow is at 37.62 degrees longitude and Brasilia is at -47.87
degrees longitude, thus the two cities are at different sides of the meridian.
Therefore, the distance </span><span>(in degrees) between the longitude lines of Moscow and Brasilia</span> is |37.62| + |-47.87| = 37.62 + 47.87 = 85.49
Triangle AGB is congruent to Triangle CGB.
Answer:
13.7142857143
Step-by-step explanation:
If you need to round then do so, or i will comment the rounded version if needed.
2x - 15
15 is decreased that is the key word here which indicates subtraction.
twice a number with given variable x is 2x
subtraction always goes behind so 2x - 15
