The answer is option C) 7.688 * 10^8.
It's simple. Just add 5 and 3. Then you will get 8. And then multiply 3.844 * 2 . You will get 7.688. After that write this down : 7.688 * 10^8.
Hope this answer will help you a lot. If it does then mark my answer as the brainliest please:)!
Answer:
Road C is 1.5 mi east of Road A
Step-by-step explanation:
we know that
Road B is 4.6 mi east of Road A
Road C is 3.1 mi west of Road B
so
Road C is between Road A and Road B
AB=4.6 miles
CB=3.1 miles
AB=AC+CB
Solve for AC
AC=AB-CB
AC=4.6-3.1=1.5 miles
therefore
Road C is 1.5 mi east of Road A
Answer:
62.4 ft²
Step-by-step explanation:
The unmarked horizontal dimension at the bottom of the triangle is ...
(8 ft)sin(30°) = 4 ft
The unmarked vertical dimension of the triangle (the height of the trapezoid) is ...
(8 ft)cos(30°) ≈ 6.93 ft
Then the area of the trapezoid is given by the formula ...
A = (1/2)(b1 +b2)h
A = (1/2)((4 ft+7 ft) +(7 ft))(6.93 ft) ≈ 62.4 ft²
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The mnemonic SOH CAH TOA can remind you of the relationships between right triangle dimensions and angles.
Sin = Opposite/Hypotenuse ⇒ Hypotenuse×Sin = Opposite
Cos = Adjacent/Hypotenuse ⇒ Hypotenuse×Cos = Adjacent
The idea being, when you run a perpendicular line to the base, from the right-angle in a right-triangle, like in this case, what you end up with is, three similar triangles, a Large triangle containing the two smaller ones, a Medium triangle and a Small one, check the picture below.
since all three are similar, we can use the proportions on the corresponding sides, as you see in the picture, the base of the triangle then will just be x + y.
Answer:
The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
Step-by-step explanation:
