Mug 2 can hold the most as its volume is greater than that of mug 1
Step-by-step explanation:
To find out which mug holds more let us find the volume of each mug
As we know
Height of first mug =H1= 3 in
Diameter of first mug= D1= 5.5 in
Radius of first mug = R1= ![\frac{5.5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5.5%7D%7B2%7D)
= 2.75 in
The volume of first mug M1 is V1
The formula used will be
V=πr2h
V1 will be equal to
![V1=\pi r_{1} 2 h_{1} \\V1= \pi (2.75) (2) (3)\\V1= 51.81](https://tex.z-dn.net/?f=V1%3D%5Cpi%20r_%7B1%7D%20%202%20h_%7B1%7D%20%5C%5CV1%3D%20%5Cpi%20%282.75%29%20%282%29%20%283%29%5C%5CV1%3D%20%2051.81)
V1 = 51.81
Similarly
As we know
Height of second mug = H2= 4 in
Diameter of second mug = D2 = 4.5 in
Radius of second mug = R2= ![\frac{4.5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B4.5%7D%7B2%7D)
= 2.25 in
The volume of second mug M2 is V2
the formula used will be
V=πr2h
V2 will be equal to
![V2= \pi r_{2} 2h_{2} \\V2 = \pi (2.25)(2)(4)\\V2 = 56.52](https://tex.z-dn.net/?f=V2%3D%20%5Cpi%20r_%7B2%7D%202h_%7B2%7D%20%5C%5CV2%20%3D%20%20%5Cpi%20%282.25%29%282%29%284%29%5C%5CV2%20%3D%2056.52)
V2 = 56.52
So as V2(56.52) is greater than V1(51.81) so mug 2 can hold the most
Keywords: volume of cylinder
Learn more about volume of cylinder at:
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Answer: 12x^3 + 19x^2 -27x -40
Step-by-step explanation:
Finding f(x) times g(x) is multiply the two polynomials
(4x+5)(3x^2 + 1x -8) Apply the distributive property twice to solve
4x ( 3x^2 + 1x -8)
12x^3 + 4x^2 - 32x
5(3x^2 + 1x -8)
15x^2 + 5x - 40
12x^3 + 4x^2 - 32x + 15x^2 + 5x -40 now combine like terms
12x^3 + 19x^2 -27x -40
Answer:
(-2x^4y^2)^3
the solution is -8x^12y^6
Step-by-step explanation:
Area of semicircle = (πr²) ÷ 2
Area of semicircle:
= (3.14)(2)² ÷ 2
= (3.14)(4) ÷ 2
= 12.56/2
= 6.28
Answer:
Step-by-step explanation:
Select the correct answer from each drop-down menu.
We solve using z score formula
z-score is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
The average time taken to complete a test follows normal probability distribution with a mean of 70 minutes and a standard deviation of 25 minutes.
a) The probability of a randomly selected student completing the test in 45 minutes or less is approximately equal to %.
z = 45 - 70/25
b) The probability of a randomly selected student completing the test in 95 minutes is %.
z = 95 - 70/25