I dont know the question sory
ANSWER
9.5
EXPLANATION
To find the distance between home and work, we have to use the formula:
![D\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We have that home is at point (3, -3) and work is at point (0, 6).
Therefore:
(x1, y1) = (3, -3)
(x2, y2) = (0, 6)
Therefore, we have that:
![\begin{gathered} D\text{ = }\sqrt[]{(0-3)^2+(6-(-3))^2} \\ D\text{ = }\sqrt[]{(-3)^2+(6+3)^2}\text{ = }\sqrt[]{(-3)^2+(9)^2} \\ D\text{ = }\sqrt[]{9\text{ + 81}}\text{ = }\sqrt[]{90} \\ D\text{ = 9.5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%280-3%29%5E2%2B%286-%28-3%29%29%5E2%7D%20%5C%5C%20D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%28-3%29%5E2%2B%286%2B3%29%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%28-3%29%5E2%2B%289%29%5E2%7D%20%5C%5C%20D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B9%5Ctext%7B%20%2B%2081%7D%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B90%7D%20%5C%5C%20D%5Ctext%7B%20%3D%209.5%7D%20%5Cend%7Bgathered%7D)
The answer is 9.5
Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Answer:
25
Step-by-step explanation:
You can get that the common difference for all of the terms if four by finding the difference between -3 and 5, which gives us four. Using this, we can calculate the last term by doing 5+4*5 which is 25.
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