Step-by-step explanation:
Given the geometric sequence
8 + 6 + 4.5...
A geometric sequence has a constant ratio and is defined by























∵ 


∵
, 
so
∵ 

∵ 
∵ 
Therefore, the sum of the first 25 terms in this geometric series: 31.98
Multiple both sides by 5/1 and get
-1/1 • (x-4) = -10/1
divide the numbers and get
-1 • (x-4) = -10
remove the parentheses
- x-4 = 10
move the constant to the right
-x = -10-4
calculate
-x = -14
change the signs
x= 14
Answer:I think it’s 61 minutes
Step-by-step explanation:
Y = 3x + 4
y = 3x + 7
3x + 4 = 3x + 7
3x - 3x = 7 - 4
0 = 3.....incorrect....this system has no solutions because ur lines are parallel and they never cross.
or look at it this way..
y = 3x + 4
y = 3x + 7
both have slopes of 3...but the y intercepts are different......when this happens, it means the lines are parallel with no solution
Answer:
a or c would be your answer hope this helps
Step-by-step explanation: