Help me for number 13,14,15 QUICKLY FAST

Mathematics

2 answers:

SashulF [63]3 years ago

8 0

13. they are not, because the parentese's make it different by applying the order of operations to the two sections, rather than in a long line.

the first one is equal to 1/40 1/4 * 10 = 1/40
second one is equal to 3/8 10 / 40 / 2 *5 = .25 / 2 * 5 = 3/8

14. g + w = 40 since there are both grape and watermelon in the entire jar of 50

15. algebraic because it involves variables and not just numbers dependent on PEMDAS

abruzzese [7]3 years ago

8 0

13. No. If you were to do the exertion with pertness, you would have to:
A) Divide 10 by 40 and get 0.4
B)Divide 0.4 by 5 and get 0.08
C) Multiply 0.08 by 2 and get 0.16

If you were to do PEMDAS for the first one, you would first do the perentasis first:
A) Divide 10 by 40 and get 0.4
B) Multiply 5 by 2 and get 10
C) Divide 0.4 by 10 and get 0.04

These aren't the same.

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor

vodomira [7]

Step-by-step explanation:

$\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\ \\ \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\ \\ \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x} \\ \\ \therefore \: x - 5+ 25 = 3 \sqrt{x} \\ \\ \therefore \: x + 20 = 3 \sqrt{x} \\ \\ squaring \: both \: sides \\ (x + 20)^{2} = ( {3 \sqrt{x} })^{2} \\ \therefore \: {x}^{2} + 40x + 400 = 9x \\ \therefore \: {x}^{2} + 40x + 400 - 9x = 0 \\ \therefore \: {x}^{2} + 31x + 400 = 0 \\$