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ELEN [110]
3 years ago
8

Help me for number 13,14,15 QUICKLY FAST

Mathematics
2 answers:
SashulF [63]3 years ago
8 0
13. they are not, because the parentese's make it different by applying the order of operations to the two sections, rather than in a long line.

the first one is equal to 1/40     1/4 * 10 = 1/40   
second one is equal to 3/8     10 / 40 / 2 *5 = .25 / 2 * 5 =  3/8

14. g + w = 40  since there are both grape and watermelon in the entire jar of 50

15. algebraic because it involves variables and not just numbers dependent on PEMDAS
 

abruzzese [7]3 years ago
8 0
13. No. If you were to do the exertion with pertness, you would have to:
A) Divide 10 by 40 and get 0.4
B)Divide 0.4 by 5 and get 0.08
C) Multiply 0.08 by 2 and get 0.16

If you were to do PEMDAS for the first one, you would first do the perentasis first:
A) Divide 10 by 40 and get 0.4
B) Multiply 5 by 2 and get 10
C) Divide 0.4 by 10 and get 0.04

These aren't the same.
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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor
vodomira [7]

Step-by-step explanation:

\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

8 0
4 years ago
Given that A, O &amp; B lie on a straight line segment, evaluate COD.
GrogVix [38]
(3x + 94) I’m not sure
8 0
3 years ago
Read 2 more answers
How do you find the circumference of a circle?
neonofarm [45]
Prefer this webpage
http://www.mathopenref.com/circumference.html
4 0
3 years ago
Can someone help me on this? Quite lost
zloy xaker [14]

answer:

2. 3/2

1. y=-7

Step-by-step explanation:

6 0
3 years ago
Which are correct representations of the inequality 6x ≥ 3 + 4(2x – 1)? Check all that apply.
Verdich [7]

Answer:

6x ≥ 3 + 4(2x - 1)

⇔ 6x ≥ 3 + 8x - 4        => remove the parentheses

⇔ 6x - 8x ≥ 3 - 4

⇔ -2x ≥ -1

⇔ 2x ≤ 1 (or 1 ≥ 2x)

⇔ x ≤ 1/2

⇔ x ≤ 0.5

The answer for the question should be:

1 ≥ 2x

6x ≥ 3 + 8x – 4

and the first graph.

6 0
3 years ago
Read 2 more answers
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