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Lunna [17]
3 years ago
14

mula1" title="\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x}" alt="\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vodomira [7]3 years ago
8 0

Step-by-step explanation:

\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

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Pls help me and thank ya!!
algol13

Answer:

Option 1

Step-by-step explanation:

Rational numbers do not have infinite decimals.

Option 1:

-5, 3/4 and √49 are all rational. Correct

√49 = 7

3/4 = 0.75

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Option 2:

1/4 = 0.25

5 = 5

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Incorrect

Option 3:

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Option 4:

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5 0
3 years ago
I need help please?!):
motikmotik

Answer:

Option C:   $ \sqrt{\textbf{121}} $

Step-by-step explanation:

Given the side length of a square is 11 units.

Note that $ \sqrt{121} = \pm 11 $

Since, length cannot be negative, we can eliminate - 11.

Hence, the length of the side of the square is 11 units = $ \sqrt{11^2} = \sqrt{121} $.

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7 0
3 years ago
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6 0
3 years ago
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3 years ago
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ivann1987 [24]

Answer:

2(4a - 4b) + 4(3a + 2b) = 20a

Step-by-step explanation:

2(4a - 4b) + 4(3a + 2b)

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Thus, 2(4a - 4b) + 4(3a + 2b) = 20a

<u>-TheUnknownScientist</u>

4 0
3 years ago
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