Answer
6x−11y−z
Step-by-step explanation:2x−5y−2z+4x−6y+z
=2x+−5y+−2z+4x+−6y+z
Combine Like Terms:
=2x+−5y+−2z+4x+−6y+z
=(2x+4x)+(−5y+−6y)+(−2z+z)
=6x+−11y+−z
w = ¼
so 12w= 3
because we set it up like 5w-1= w then subtract the w so it’s on the same side as the other w. then we add the one and divide the one by 4 to get the w by itself. then you plug the ¼ into the equation 12(w) to equal 3!
Answer:
209
Step-by-step explanation:
You would first create an explicit formula for the provided sequence.
The basic explicit formula for arithmetic sequences is
, where an is the number of the term, d is the number you are adding or subtracting by, n the location of the term, and a1 is the first number.
We would then substitute the values given into the formula.
We are trying to solve the value of the 52nd term. This makes n = 52. The first number of the sequence is 5, so a1 is 5. Finally, d is 4 because we are adding 4 to each number in the sequence.
Therefore, our resulting equation would be
, which equals 209.
Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
Answer:
<h2><em><u>No Solutions</u></em></h2>
Explanation:
2(x + 1) = 2x + 1
- Simplify both sides of the equation
2(x + 1) = 2x + 1
(2)(x) + (2)(1) = 2x + 1 [Distribute]
- Subtract 2x from both sides
2x + 2 − 2x = 2x + 1 − 2x
2 = 1
- Subtract 2 from both sides
2 − 2 = 1 − 2
0 = −1
<h2><u><em>This Is False, Therefore There Are No Solutions</em></u></h2>
- PNW