3 years ago

The position of a digit in a number that determines its value

1 answer:

4 0

So in long numbers or any number the positon determines its in the ones, tenths, hundredths

e.g
658
6 is in the hundredths as it is technically 600
5 is in the tenths as it is 50
8 is the ones as its just 8

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X2 + 5x - 50 = 0<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%205x%20-%2050%20%3D%200" id="TexFormula1" ti

love history [14]

Answer:

x = -10

x = 5

Step-by-step explanation:

${x}^{2} + 5x - 50 = 0 \\ (x + 10)(x - 5) = 0 \\ \\ x = - 10 \\ x = 5$

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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