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3 years ago

Write a polynomial function in factored form w zeros at -2,5,6

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

Step-by-step explanation:

The zeros of a polynomial are the solutions to the function. They are found from the factors. The factors which multiply to make the equation in standard form. To write the factors reverse the process by unsolving the factor.

x = -2 comes from x+2

x = 5 comes from x-5

x = 6 comes from x-6

The factored form is (x+2)(x-5)(x-6).

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What is the domain and range of the relation [(1, -8), (-7,8), (-3, 7). (-3, -5]?

Nadusha1986 [10]

Step-by-step explanation:

domain = {-7, -3, 1}

range ={-8, -5, 7, 8}

6 0

3 years ago

klasskru [66]

Answer:

2. y - 2 = -1/6(x + 10)

3. y - 1 = -1/6(x + 4)

5. y = -1/6x + 1/3

Step-by-step explanation:

hope this helps!

8 0

2 years ago

1. Find the measurement of angle J.<br><br> 2. (5x - 13) (3x + 17)

Alex Ar [27]

Answer:

Q1. x= 18, y=59

Q2. m∠J= 56°

Step-by-step explanation:

Q1. (3x +5)°= y° (base ∠s of isos. △)

y= 3x +5 -----(1)

(3x +5)° +y° +(4x -10)°= 180° (∠ sum of △)

3x +5 +y +4x -10= 180

7x +y -5= 180

7x +y= 180 +5

7x +y= 185 -----(2)

Substitute (1) into (2):

7x +3x +5= 185

10x= 185 -5

10x= 180

x= 180 ÷10

x= 18

Substitute x= 18 into (1):

y= 3(18) +5

y= 59

Q2. (5x -13)°= (3x +17)° (base ∠s of isos. △)

5x -13= 3x +17

5x -3x= 17 +13

2x= 30

x= 30 ÷2

x= 15

∠LKJ

= 3(15) +17

= 62°

∠KLJ= 62° (base ∠s of isos. △)

m∠J

= 180° -62° -62° (∠ sum of △JKL)

= 56°

8 0

3 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago

Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces