Which expressions are equivalent to

Imena's math test scores are 83, 93, 78, 89, and 83. She has one more math test this semester. What score most she get on the te

marshall27 [118]

87 is the median because 83 and 87's average is 85.

8 0

2 years ago

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True or false. the points on a line can be paired one to one with real mumbers

frosja888 [35]

This is true, because there is an infinite amount of real numbers in both, and they are both countably infinite (so these infinities are equal). Hope this helps!

3 0

3 years ago

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A map of a new dog park shows that it is triangular and that the sides measure 18.5m, 36.9m, and 16.9m. Are the dimensions corre

r-ruslan [8.4K]

In order to check whether the length of the sides are applicable to form a triangle is that we have to make sure that the sum of the length of two side should be greater than the third side.

18.5 m, 36.9 m, and 16.9 m
18.5 m < 36.9 m +16.9 m
36.9 m < 18.5 m +16.9 m
16.9 m < 18.5 m + 36.9 m

So the dimensions are correct!

5 0

2 years ago

A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

Step-by-step explanation:

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$

⇒ $probability = \frac{(17)}{52}$

⇒ $probability =0.3269$

Therefore, probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

8 0

2 years ago

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i need the answer and if possible, can you show your work? i would like to know the steps. Please and thanks you

lisov135 [29]

Answer: The volume would be 61.261.

Step-by-step explanation: To find the volume of a sector of a cylinder use the following formula and fill in the variables with the appropriate data. V = π r² h * Θ / 360°

7 0

2 years ago