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viva [34]
3 years ago
10

What is the answer 45w + 123.95 = 753.95

Mathematics
2 answers:
andrey2020 [161]3 years ago
8 0

subtract 123.95 from both sides

45w = -630

divide both sides by 45

w = -14

expeople1 [14]3 years ago
3 0

Answer:

the answer is 14 your welcome :)

Step-by-step explanation:

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Turn the sentence into an expression please
Hatshy [7]

Answer:

x + 5x

Step-by-step explanation:

X is the variable in this case, or 'a number.' This number x is added to the product of 5 and the number, or 5x. Therefore the expression is x+5x. It can also be simplified to 6x.

7 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible
djverab [1.8K]

\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\&#10;\\&#10;\text{we know that the product of LCM and HCF of any two numbers is equal}\\&#10;\text{to the product of the numbers. that is}\\&#10;\\&#10;\text{HCF}\times \text{ LCM}=p\times q\\&#10;\\&#10;\Rightarrow 59 \times \text{LCM}=590\\&#10;\\&#10;\Rightarrow \text{LCM}=\frac{590}{59}\\&#10;\\&#10;\Rightarrow \text{LCM}=10\\&#10;\\&#10;\text{for any two natural numbers, their Least Common Multiple (LCM) is always}

\text{greater than their HCF.}\\&#10;\\&#10;\text{but here we can see that }LCM

Hence there is no such natural numbers exist.

7 0
3 years ago
Catherine sells bags of popcorn at the theatre. The bags come in three sizes.
Nookie1986 [14]

Answer:

The answer is the most reasonable one which I think large is

Step-by-step explanation:

Because it's only 100 grams more and $2 bucks seems like a good deal

6 0
3 years ago
2.1.43 A particular hybrid car travels approximately 235 mi on 5 gal of gas. Find the amount of gas required for a 705-mi trip.
o-na [289]

Answer: 15 gallons of gas is required for a 705 miles trip.

Step-by-step explanation:

Since we have given that

Number of miles in a trip = 235 miles

Number of gallon of gas is needed = 5

We need to find the amount of gas required for 750 miles trip.

Since there is direct variation, as for increase in number of miles, amount of gas must be increased.

According to question, it becomes,

\dfrac{235}{5}=\dfrac{705}x}\\\\47=\dfrac{705}{x}\\\\47x=705\\\\x=\dfrac{705}{47}\\\\x=15\ gallons

Hence, 15 gallons of gas is required for a 705 miles trip.

7 0
3 years ago
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