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Naddik [55]
2 years ago
8

Someone help me please

Mathematics
1 answer:
kherson [118]2 years ago
4 0

Answer:

I will just choosé the second one

Because it is possible to compare sizes In one triangle rather than comparing with another one which we don't reàlly know of its sizes.

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KiRa [710]
For x\ \textgreater \ 0, 2^x\ \textless \ 3^x, all the more 2^x\ \textless \ 3^x+1, therefore no solution.

For x=0, we have 2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2. Obviously that' false.

For x\ \textless \ 0 both 2^x and 3^x, where 2^x\ \textgreater \ 3^x, belong to the range (0,1), then 3^x+1 belong to the range (1,2).
Those ranges don't have a common part, therefore, again, no solution.

So, the equation 2^x=3^x+1 doesn't have a solution.

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Here, "disjointed" signifiies that Event A and Event B are independent; neither outcome influences the other.  In such a case, the union of A and B is given by the sum of the two probabilities P(A) and P(B).

Here, that sum is P(A or B) = 6/25 + 9/25, or 15/25, or 0.6.


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