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3 years ago

If s(x) = 2x2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =

2 answers:

Nookie1986 [14]3 years ago

8 0

You simply multiply the two and distribute to solve. I am starting with t(x) because I think it is easier.

(x+4)*(2x^2+3x-4)
2x^3+3x^2-4x+8x^2+12x-16 (distribute)
2x^3+11x^2+8x-16 (combine like terms)

Nostrana [21]3 years ago

8 0

2x^3+11x^2+8x-16 ...............

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PLZ HELP I WILL MARK BRAINLEST IF CORRECT

Nataly_w [17]

they are equal or congruent because if you look at it they both are right triangles

4 0

4 years ago

Dan's school is selling tickets to a play. On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets

VashaNatasha [74]

Answer:

Let's define the variables:

A = price of one adult ticket.

S = price of one student ticket.

We know that:

"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."

1*A + 6*S = $69

"The school took in $150 on the second day by selling 7 adult tickets and student tickets"

7*A + 7*S = $150

Then we have a system of equations:

A + 6*S = $69

7*A + 7*S = $150.

To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:

A = $69 - 6*S

Now let's replace this in the other equation:

7*($69 - 6*S) + 7*S = $150

Now we can solve this for S.

$483 - 42*S + 7*S = $150

$483 - 35*S = $150

$483 - $150 = 35*S

$333 = 35*S

$333/35 = S

$9.51 = S

That we could round to $9.50

That is the price of one student ticket.

4 0

3 years ago

HELP ME ON THIS QUESTION ASAP!!!!!

Naya [18.7K]

The answer is 2

Y2-Y1 / X2-X1

7 0

3 years ago

If the hypotenuse of a right triangle is 6 feet long, and one leg is 5 feet long,

Anestetic [448]

C^2=a^2+b^2
6^2=5^2+b^2
36=25+b^2
b^2=36-25
b^2=11
b= √11
b=3.3166
If you need to round it to the tenth place,
b~3.3
to hundreds place,
b~3.32
Good luck

6 0

3 years ago

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym Tw

mr_godi [17]

Answer: (15th street, 14th Avenue)

Step-by-step explanation:

Given the following :

Ping's residence = (3rd street, 6th Avenue)

Ari's residence = (21st street, 18th Avenue)

Gym location = 2/3 the distance of Ping's residence to Ari's residence

So, distance between Ping's home to Ari's home

Distance = (21st street, 18th Avenue) - (3rd street, 6th Avenue)

Distance = (21 - 3) street, (18 - 6) avenue

Distance between ping and Ari = (18th , 12th )

Gym distance = 2/3 of distance between ping and Ari

Gym distance = 2/3 × (18), 2/3 ×(12)

Gym distance = (12, 8)

Gym location = Ping's location + gym distance

Gym location = (3rd street, 6th Avenue) + (12th street, 8th Avenue)

Gym location = (15th street, 14th Avenue)

3 0

3 years ago