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Mice21 [21]
3 years ago
12

A room is 4 m wide and 1.5 times as long as it is wide. Its height is 1/2 the length. Find the mass of the air in the room if 1m

^3 of air weighs approximately 1 3/10 kg.
Mathematics
2 answers:
Elena L [17]3 years ago
8 0

Answer: 93.6

Step-by-step explanation:

Width: 4

Length: 4*1.5=6

Height: 6/2=3

4*6*3=72

72*1 3/10= 93.6

Dahasolnce [82]3 years ago
7 0

Answer:

Step-by-step explanation:

length = 1.5*4 = 6 m

height = 6/2 = 3m

Volume of room = l*b*h

= 6 * 4 * 3 = 72 cubic m

Mass of air = 1.3 * 72 = 93.6 Kg

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Please help me solve this. This is in logarithm functions. Thank you...<br><br><br> Solve log x = 3.
stepan [7]

Since no base is given, assume the base to be 10 and solve.

log base 10 of x = 3

x=10^3

x=1000

5 0
3 years ago
Read 2 more answers
A slug takes 4.25 minutes to travel 11.2 centimeters. What is the speed of the slug in meters per second?
MAXImum [283]

Answer:

4.39*10^{-4}\ m/sec

Step-by-step explanation:

Remember that

1\ m=100\ cm

1\ min=60\ sec

The speed is equal to divide the distance by the time

Convert the units

4.25\ min=4.25(60)=255\ sec

11.2\ cm=11.2/100=0.112\ m

so

0.112/255=0.000439\ m/sec

4.39*10^{-4}\ m/sec

5 0
4 years ago
Identify the 34th term of the arithmetic sequence 2, 7, 12
torisob [31]
The equation is AN=A1+D(N-1) A1 being the first number (2) D being the difference (in this case 5) and N being the nth term to find (34) so here you have AN=2+5(34-1) then AN=2+5(33). the answer here is 167.
5 0
4 years ago
What is the area<br>what is the perimeter <br><br>Please answer Quickly ​
Maru [420]

Answer:

34 cm; 48 cm^2

Step-by-step explanation:

5+5+12+12=10+24=34

12(4)=48

5 0
3 years ago
A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then
Kobotan [32]

Complete Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?

Answer:

The equation is 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

Step-by-step explanation:

From the question we are told that

The velocity of the bee is v =  9ft/s =

The duration on the flowerbed is t =  13 \  minutes  =  780 \  s

The velocity back to his hive is u = 6ft / s

The total time away from it hive is t_t  =  16 \  minutes  =  960  \ s

Now let assume the distance of the flower bed from the hive is Z

Generally the time taken for the bee to travel to the flower bed from its hive is

t_1 =  \frac{Z}{9}

The time taken for the bee to fly back to his hive is

t_2 =  \frac{Z}{6}

Generally the total time the bee spent outside of his house is mathematically represented as

t_t  =  t_1 + t_2 +  t

=> 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

6 0
3 years ago
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