how many four-digit numbers are possible in which the leftmost digit is odd, the rightmost digit is even, and all four digits ar

Question

Serggg [28]

4 years ago

7

how many four-digit numbers are possible in which the leftmost digit is odd, the rightmost digit is even, and all four digits ar

e different

Mathematics

2 answers:

FromTheMoon [43] · Answer 1 · 2021-11-19T20:59:46+03:00

FromTheMoon [43]4 years ago

8 0

1188 is my answer malee2021 sheesh ☺

vfiekz [6] · Answer 2 · 2021-11-19T23:26:48+03:00

vfiekz [6]4 years ago

3 0

Answer:

1400

Step-by-step explanation:

Count from left to right: There are 5 choices for the first digit, 5 choices for the second, 8 remaining choices for the third, and 7 remaining for the fourth, so there are $5*5*8*7= 1400

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