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dlinn [17]
3 years ago
10

ILL GIVE THE BRAINLIEST pls help me with this question EVERYTHING IS IN THE PICTURE PLS HELP DUE TODAY ​​IF YOU PUT A WRONG ANSW

ER ILL REPORT YOU FASTER THAN ASSIGMENT IS DUE ​​

Mathematics
2 answers:
Sloan [31]3 years ago
8 0

Answer:

186.2 :)

Step-by-step explanation:

Blababa [14]3 years ago
7 0

Answer:

186.2 in^2

Step-by-step explanation:

7*9.5*2.8=186.2

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It's probably A (I can't tell you for certain, because I can't see the image, but the other options seem illogical).

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Find dy/dx for 4 - xy = y^3
storchak [24]

Answer:

\frac{dy}{dx}=-\frac{y}{3y^2+x}

Step-by-step explanation:

4-xy=y^3

dy/dx=?

\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}

Solving for dy/dx: Addind x dy/dx both sides of the equation:

-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}

Common factor dy/dx on the right side of the equation:

-y=(3y^2+x)\frac{dy}{dx}

Dividing both sides of the equation by 3y^2+x:

\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}

7 0
3 years ago
Solve for x.<br> 3х - 4 = 13
dybincka [34]

\large\bold{\underline{\underline{  \: x = 5  \frac{2}{3}   }}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

3x - 4 = 13

➺ \: 3x = 13 + 4

➺ \: 3x = 17

➺ \: x =  \frac{ 17}{3}

➺ \: x = 5  \frac{2}{3}

\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}

➺ \: 3x - 4 = 13

➺ \: 3 \times 5 \frac{2}{3}   - 4 = 13

➺ \: 3 \times  \frac{17}{3}  - 4 = 13

➺ \: 17 - 4 = 13

➺ \: 13 = 13

➺ L. H. S. = R. H. S.

Hence verified.

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}

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Answer:

Step-by-step explanation:

28

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