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Crazy boy [7]
3 years ago
10

How to find the measure of angles?

Mathematics
1 answer:
nevsk [136]3 years ago
7 0

Answer:

The best way to measure an angle is to use a protractor. To do this, you'll start by lining up one ray along the 0-degree line on the protractor. Then, line up the vertex with the midpoint of the protractor. Follow the second ray to determine the angle's measurement to the nearest degree.

Step-by-step explanation:

You might be interested in
A rectangle has side lengths 2x + 3 and 5x - 2.
xz_007 [3.2K]

Answer:

10x² + 11x - 6

Step-by-step explanation:

The area (A) is the product of the sides, that is

A = (2x + 3)(5x - 2) ← expand using FOIL

   = 10x² - 4x + 15x - 6 ← collect like terms

   = 10x² + 11x - 6

5 0
3 years ago
I need help with this
Angelina_Jolie [31]
Answer: 256

F(8)=512- 768
F(8)= 256
Hopes this helps
3 0
1 year ago
What is the approximate area of the circle shown below?<br> ???? Help ???
PIT_PIT [208]

Answer:

D. 1662 cm

Step-by-step explanation:

A=πr2=π•23≈1661.90251cm²

which is 1661.9

but of course you have to round up for 1662 cm :)

7 0
2 years ago
Descried how to derive the quadratic formula from a quadratic equation in standard form
Aleks [24]

Answer:

The standard form of a quadratic equation is:

ax^2+bx+c=0, a\neq 0

Quadratic Formula Derivation:

ax^2+bx+c=0\\

$x^2+\frac{b}{a}x+\frac{c}{a} =0 $

$x^2+\frac{b}{a}x = -\frac{c}{a}$

Completing the Square:

$x^2+\frac{b}{a}x +\frac{b^2}{4a^2} = \frac{b^2}{4a^2}-\frac{c}{a}$

$  ( x+\frac{b}{2a} )^2 =  \frac{b^2-4ac}{4a^2}  $

Square Root property:

$x+\frac{b}{2a}  = \pm \sqrt{ \frac{b^2-4ac}{4a^2}}   $

$x  = -\frac{b}{2a} \pm  { \frac{\sqrt {b^2-4ac}}{2a}}   $

$x  =  \frac{-b\pm\sqrt{b^2-4ac}} {2a}  }   $

8 0
2 years ago
It's 12 points of u get this right<br>​
earnstyle [38]

Answer:

y = -2x + 8

Step-by-step explanation:

When two points are given, the equation of the line passing through the points is given by:

        $ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} $

where: $ (x_1,y_1) $ and $ (x_2,y_2) $ are the two points passing through the line.

Here, $ (x_1,y_1) = (2,4) $ and $ (x_2, y_2) = (3,2) $.

Substituting in the formula, we have:

$ \frac{y - 4}{2 - 4} = \frac{x - 2}{3 - 2} $

⇒ $ \frac{y - 4}{-2} = \frac{x - 2}{1} $

⇒ y - 4 = -2x + 4

⇒ y = -2x + 8 is the required equation of the line.

4 0
3 years ago
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