<span>Total mass of mixture is given as 5/6 pound, in which 1/4 pound is gravel. Amount of sand in the mixture will be 5/6 - 1/4 = 7/12
So, the ratio of sand to that of gravel in given mixture is 7/12:1/4 = 7:3. i.e every 10
parts of mixture contain 7 parts of sand and 3 parts of gravel.
If we are given 1-pound of same mixture, it will contain 1 * 3/10 pound gravel, i.e. 0.3 pound.</span>
All sides and angles are congruent
C.
8 1/4
<span> -32/3x(-21/4) Simplify
Thats when you sill get your answer which the solution is 8 1/4</span>
First, we can eliminate d(x) because we can see it's a linear line. We can also eliminate a(x) because it's also a linear line. Both b(x) and c(x) have an asymptote. on b(x) you can see that x = 3 is the asymptote. For c(x) if it's graphed, it has a horizontal asymptote at y = -1.
Hope this helps!
Answer:
Length of hypotenuse JH = 9.2 unit (Approx.)
Length of perpendicular JG = 6.5 unit
Step-by-step explanation:
Given:
Length of base GH = 6.5 unit
Angle of H = 45°
Find:
Length of perpendicular JG
Length of hypotenuse JH
Computation:
Using trigonometry function:
Tan θ = Perpendicular / Base
Tan 45 = Perpendicular / 6.5
1 = Perpendicular / 6.5
Perpendicular = 6.5
Length of perpendicular JG = 6.5 unit
hypotenuse = √perpendicular² + base²
Length of hypotenuse JH = √6.5² + 6.5²
Length of hypotenuse JH = √42.25 + 425.25
Length of hypotenuse JH = √84.5
Length of hypotenuse JH = 9.1923
Length of hypotenuse JH = 9.2 unit (Approx.)
