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ser-zykov [4K]
3 years ago
5

Can someone please help me with this problem !!! ASAP PLEASE NEED THE HELP !!

Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0
I would say A. is the correct answer. Definitely a weird one. Hope this helps!
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A polygon has its vertices at the following points.
seropon [69]

Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

\sqrt{(x2-x1)^2 + (y2 -y1)^2}

AB = \sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}

BC = |7-4| = 3

CD = \sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}

AD = |9-2| = 7

2) equation of the line that passes threw BC

y = 7

3) equation of the line that passes threw AD

y = 5

conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

3 0
2 years ago
Which property can be justified using the ratios in triangle XYZ ?
Alenkasestr [34]
The correct answer is B.

Determine and recall first the trigonometric functions:

Sin A = Opposite/Hypotenuse
Cos A = Adjacent/Hypotenuse
Tangent = Opposite/Adjacent

If for example we try to take an angle, for example the Y, then Y is opposite Y. The Hypotenuse will be the longer side which is going to denoted by X and the next side will be Adjacent which will be denoted by Z. 

Use this test to answer:

Sin Y = Y/X

where:

Y = opposite
X = hypotenuse 

Cos (90 - y) = cos (90 - 50) = cos 40

where Z = 40
we look for cos Z = Y/X

Therefore,

Sin Y = Cos (90 - Y) 

6 0
3 years ago
Read 2 more answers
Change this root below into a power.
Elena L [17]

Answer:

5^{1/2}

Step-by-step explanation:

6 0
2 years ago
What is the answer to this?
NARA [144]

Answer:

See work for 3 answers

Step-by-step explanation:

You can add the exponents

(-8)^{12}

also could be stated as

(8)^{12}

numerical value

6.87194767 × 10^{10}

5 0
3 years ago
Sophie bikes at a speed of s miles per hour. Her friend Rana is slower, her biking speed is only r miles per hour.
Rzqust [24]
2x 23 8>×××683 83u2 282i2 e7uwww2uw727w828282828i882iii29owo999292
8 0
2 years ago
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