Answer:
11860.22 rev/hour
Step-by-step explanation:
The diameter if a cylinder, d = 21.02 inches
Radius, r = 10.51 inches
or
r = 0.875 feet
The linear speed of a point on the cylinder's surface is 18.12 ft/sec.
We need to find the angular speed of the cylinder.
The relation between the linear speed and the angular speed is given by :
Where
is angular speed
or
So, the required angular speed of the cylinder is 11860.22 rev/hour.
Answer:
(6 - √ 100 - 6 * 6) 3 - 9 ÷ 3 = -64003/1 = -64003
Step-by-step explanation:
1.Square root: sqrt(100) = √ 100 = 10
2.Subtract: 6 - the result of step No. 1 = 6 - 10 = -4
3.Multiple: 6 * 6 = 36
4.Subtract: the result of step No. 2 - the result of step No. 3 = -4 - 36 = -40
5.Exponentiation: the result of step No. 4 ^ 3 = (-40) ^ 3 = -64000
6.Divide: 9 / 3 = 3
7.Subtract: the result of step No. 5 - the result of step No. 6 = -64000 - 3 = -64003
Answer:
should be 17
Step-by-step explanation:
find what x is by setting the equations equal to each other. (x=8) Just plug 8 into the equation to get the answer: 17
If it is homework i cant help you
sorry
