Question

PLEASE HELP .........

Answer 1

Answer:

11860.22 rev/hour

Step-by-step explanation:

The diameter if a cylinder, d = 21.02 inches

Radius, r = 10.51  inches

or

r = 0.875 feet

The linear speed of a point on the cylinder's surface is 18.12 ft/sec.

We need to find the angular speed of the cylinder.

The relation between the linear speed and the angular speed is given by :

$v=r\omega$

Where

$\omega$ is angular speed

$\omega=\dfrac{v}{r}\\\\\omega=\dfrac{18.12}{0.875}\\\\\omega=20.7\ rad/s$

or

$\omega=11860.22\ rev/hour$

So, the required angular speed of the cylinder is 11860.22 rev/hour.